#MySQL #tutorial #course SELECT first_name, last_name, hourly_pay, (SELECT AVG(hourly_pay) FROM employees) AS avg_pay FROM employees; SELECT first_name, last_name FROM customers WHERE customer_id IN (SELECT DISTINCT customer_id FROM transactions WHERE customer_id IS NOT NULL);
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SELECT first_name, last_name, hourly_pay, (SELECT AVG(hourly_pay) FROM employees) AS avg_pay FROM employees; SELECT first_name, last_name FROM customers WHERE customer_id IN (SELECT DISTINCT customer_id FROM transactions WHERE customer_id IS NOT NULL);
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Last Updated: May 22, 2026
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